- Specification route
- RP12
- Question bank
- 12 questions
- Course stage
- Year 13 / A-level only
Sample questions
A student uses a randomly placed quadrat to estimate the percentage cover of moss in a field. What is the main advantage of measuring 'percentage cover' instead of counting individual plants?
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How do you count one single piece of grass in a lawn?
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Answer: It is much faster and more accurate for plant species that grow in dense clumps where individual organisms are impossible to distinguish.
Required practical 12. For species like moss or grass that lack distinct individual boundaries, counting frequency is impossible. Percentage cover is an efficient alternative to estimate abundance.
A student is using an interrupted belt transect to survey a large sand dune system. What does 'interrupted' mean in this context?
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Doing it continuously over a $500m$ dune would take weeks.
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Answer: Quadrats are placed at regular, set intervals (e.g., every $5$ metres) along the line, rather than continuously end-to-end.
Required practical 12. An interrupted belt transect involves taking samples at defined intervals along the transect line. It is highly efficient for capturing gradual environmental changes over very long distances without sampling every single square meter.
When estimating the population of daisies in a uniform, flat field, why is 'random sampling' the most appropriate method?
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If the whole field is basically the same, you just need a fair, unbiased snapshot of the whole area.
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Answer: Because the environment is uniform, random sampling removes investigator bias, ensuring every part of the field has an equal chance of being selected, providing a representative estimate.
Required practical 12. Random sampling is used in uniform habitats. It eliminates human bias (e.g., throwing a quadrat towards the most flowers), ensuring the calculated mean is statistically valid for the whole area.
How should a student properly generate coordinates for random quadrat placement?
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Throwing objects is not mathematically random.
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Answer: By laying out two tape measures at right angles to form a grid, and using a random number generator or table to select the $x$ and $y$ coordinates.
Required practical 12 / AT k. True randomness requires a grid and a mathematical generation of coordinates to completely remove subconscious human bias.
In a woodland, a student wants to see how the abundance of bluebells changes from the dark centre of the woods out into the bright open field. What is the correct sampling technique?
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When investigating a change over a distance (an environmental gradient), you use a line.
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Answer: A belt transect (continuous or interrupted), systematically placing quadrats along a tape measure extending from the woods to the field.
Required practical 12 / AT k. Systematic sampling (transects) is used when investigating how species distribution correlates with a changing abiotic factor (like light intensity moving out of a forest).
When deciding how many quadrat samples to take in a large field, how does a student know they have taken 'enough' samples?
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As the sample gets larger, extreme anomalies have less effect on the average.
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Answer: They calculate a running mean after each sample; when the running mean stabilises and stops fluctuating significantly, enough samples have been taken.
Required practical 12. A running mean tracks the average as new data is added. Once it plateaus, the sample size is large enough to be representative of the whole population, and further sampling will not change the mean significantly.
Why might a researcher choose to record the 'percentage cover' of a plant species in a quadrat rather than its 'frequency' (number of individuals)?
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Try counting exactly how many 'plants' of grass are in a $1m \times 1m$ patch of lawn.
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Answer: Percentage cover is much faster and more accurate for species that grow in dense, continuous mats (like grass or moss) where individual plants cannot be easily distinguished.
Required practical 12. Counting frequency requires distinct individuals. For creeping, mat-forming, or highly abundant species, estimating the percentage of the quadrat area they cover is much more practical.
A student uses a $0.5m \times 0.5m$ quadrat and takes $20$ random samples in a $500m^2$ field. They count a total of $100$ buttercups. What is the estimated total population in the field?
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Area of one quadrat = $0.25m^2$. Mean per quadrat = $100 / 20 = 5$. How many quadrats fit in the whole field? $500 / 0.25 = 2000$. Total = $2000 \times 5$.
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Answer: $10,000$ buttercups
MS 0.3. Area of quadrat = $0.25m^2$. Mean number per quadrat = $100 / 20 = 5$. Total area of field = $500m^2$. Number of quadrats that fit in field = $500 / 0.25 = 2000$. Total population = $2000 \times 5 = 10,000$.
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