RP1 Effect of a named variable on the rate of an enzyme-controlled reaction

Free AQA A-level Biology RP1 questions on Effect of a named variable on the rate of an enzyme-controlled reaction, including practical reasoning, variables, data handling, clues and explanations.

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RP1
Question bank
13 questions
Course stage
AS / Year 12

Sample questions

QUESTION 1 · RP1 · LEVEL 3

When investigating the effect of substrate concentration on the rate of an enzyme-controlled reaction, why is it crucial to measure the *initial* rate of reaction?

  • Because as the reaction proceeds, substrate concentration decreases, becoming a limiting factor and slowing the rate.
  • Because the enzyme rapidly denatures after the first few seconds of the reaction.
  • Because the products of the reaction immediately evaporate, making later measurements impossible.
  • Because competitive inhibitors form spontaneously over time in the solution.
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To accurately measure how a specific concentration affects the rate, that concentration must actually be present.

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Answer: Because as the reaction proceeds, substrate concentration decreases, becoming a limiting factor and slowing the rate.

Required practical 1. The initial rate is measured (usually by drawing a tangent at $t=0$) because at the very start of the reaction, the substrate concentration is known and is not yet acting as a limiting factor.

QUESTION 2 · RP1 · LEVEL 2

When investigating the effect of temperature on an enzyme-controlled reaction, why must a buffer solution be used?

  • To maintain a constant pH, ensuring that any change in the rate of reaction is solely due to the temperature change.
  • To maintain a constant temperature throughout the entire duration of the reaction.
  • To prevent the substrate from breaking down spontaneously before the enzyme is added.
  • To provide the optimal activation energy required for the reaction to start.
Show clue

If investigating temperature (the independent variable), all other factors that affect enzyme activity must be controlled.

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Answer: To maintain a constant pH, ensuring that any change in the rate of reaction is solely due to the temperature change.

Required practical 1. A buffer maintains a constant pH. pH is a control variable when investigating temperature; if the pH fluctuates, it could denature the enzyme, invalidating the results.

QUESTION 3 · RP1 · LEVEL 2

A student sets up a control tube containing the substrate and a sample of the enzyme that has been boiled for 5 minutes. What is the specific purpose of this control?

  • To prove that the breakdown of the substrate is specifically catalysed by the active enzyme, and does not occur spontaneously.
  • To provide a baseline colour against which the end-point of the reaction can be judged.
  • To demonstrate the maximum possible rate of reaction when the enzyme is fully denatured.
  • To prove that the substrate concentration is not a limiting factor.
Show clue

Boiling denatures the enzyme. If the reaction still happens, the enzyme wasn't doing the work.

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Answer: To prove that the breakdown of the substrate is specifically catalysed by the active enzyme, and does not occur spontaneously.

A boiled enzyme control proves that the observed reaction relies on a functional enzyme with an intact active site, ruling out spontaneous breakdown or contamination.

QUESTION 4 · RP1 · LEVEL 2

When investigating the effect of temperature on the rate of an enzyme-controlled reaction, why must the enzyme and substrate be placed in the water bath in separate tubes for 5 minutes before mixing?

  • To allow both solutions to equilibrate to the target temperature so the reaction occurs at the correct temperature from the very first second.
  • To allow the enzyme's active site to permanently alter its shape to fit the substrate before they meet.
  • To denature any competitive inhibitors that might be present in the substrate solution.
  • To give the substrate time to naturally break down into simpler monomers without the enzyme.
Show clue

If you mix a cold enzyme with a cold substrate and put them in a hot water bath, the initial reaction happens while the liquids are still cold.

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Answer: To allow both solutions to equilibrate to the target temperature so the reaction occurs at the correct temperature from the very first second.

Required practical 1. Equilibration is crucial for validity. If the solutions are mixed before reaching the target temperature, the initial rate of reaction will be measured at a lower, incorrect temperature.

QUESTION 5 · RP1 · LEVEL 2

A student measures the time taken for an enzyme to completely break down a substrate. How is the rate of reaction calculated from this time data?

  • Rate = $1 / time$
  • Rate = $time / 100$
  • Rate = $time \times concentration$
  • Rate = $initial mass / time$
Show clue

Rate is a measure of how fast something happens. If it takes a long time, the rate is low. If it takes a short time, the rate is high.

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Answer: Rate = $1 / time$

Required practical 1. When the end-point of a reaction is measured by time taken (e.g., time for an 'X' to disappear in a milk powder/trypsin experiment), the rate is inversely proportional to time ($1/t$).

QUESTION 6 · RP1 · LEVEL 3

Why is it important to use a buffer solution when investigating the effect of substrate concentration on enzyme activity?

  • To keep the pH constant, ensuring the ionic bonds holding the enzyme's tertiary structure and active site together are not disrupted.
  • To keep the temperature constant, ensuring the kinetic energy of the molecules does not fluctuate.
  • To provide a constant supply of water molecules for the hydrolysis of the substrate.
  • To competitively inhibit the enzyme to ensure the reaction does not happen too quickly to measure.
Show clue

Buffers resist changes in hydrogen ion ($H^+$) concentration.

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Answer: To keep the pH constant, ensuring the ionic bonds holding the enzyme's tertiary structure and active site together are not disrupted.

Required practical 1. pH affects the charges on the amino acids making up the active site. A buffer acts as a control variable, preventing pH fluctuations from acting as a confounding variable.

QUESTION 7 · RP1 · LEVEL 3

In an experiment investigating the effect of enzyme concentration on the rate of reaction, a student sets up a negative control tube. What should this tube contain?

  • The substrate solution, the buffer, and a volume of distilled water equal to the volume of the enzyme solution.
  • The enzyme solution, the buffer, and a volume of distilled water equal to the volume of the substrate.
  • The substrate solution and the enzyme solution, but no buffer.
  • Only the enzyme solution and the substrate solution, kept at $0^\circ C$.
Show clue

A negative control proves that the reaction will not happen *without* the independent variable (the active enzyme) present.

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Answer: The substrate solution, the buffer, and a volume of distilled water equal to the volume of the enzyme solution.

Required practical 1. A negative control replaces the active component (enzyme) with an equal volume of a neutral substance (water) to prove that the breakdown of the substrate is entirely due to the enzyme and not spontaneous.

QUESTION 8 · RP1 · LEVEL 2

When plotting a graph of product formed against time for an enzyme-controlled reaction, why does the curve eventually level off and plateau?

  • The substrate concentration decreases over time and eventually runs out, meaning no more enzyme-substrate complexes can be formed.
  • The enzyme becomes completely denatured by the friction of the continuous molecular collisions.
  • The product actively inhibits the enzyme by permanently binding to the allosteric site.
  • The kinetic energy in the solution is completely used up by the reaction.
Show clue

Enzymes are not used up, but the thing they are breaking down is.

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Answer: The substrate concentration decreases over time and eventually runs out, meaning no more enzyme-substrate complexes can be formed.

Required practical 1. As the reaction proceeds, substrate is converted into product. The substrate concentration falls until it is fully depleted, at which point the reaction stops and the graph plateaus.

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