- Specification route
- AT
- Question bank
- 22 questions
- Course stage
- AS / Year 12
Sample questions
When viewing a cell under an optical microscope, how do you calibrate an eyepiece graticule?
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The graticule is just a meaningless set of lines. You need to look at a microscopic 'ruler' to give those lines physical value.
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Answer: By using a stage micrometer, which is a special slide with a microscopic scale of known length, to calculate the length of one graticule division at that specific magnification.
Apparatus and Techniques (AT d). The eyepiece graticule has arbitrary units. It is calibrated by lining it up against a stage micrometer (a slide with an exact known scale, e.g., $0.1\ mm$ divisions) to find the value of one graticule unit.
A student measures $15\ cm^3$ of a solution using a measuring cylinder with increments of $1\ cm^3$. What is the absolute uncertainty of a single reading from this measuring cylinder?
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The uncertainty is typically half of the smallest scale division.
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Answer: $\pm 0.5\ cm^3$
PS 3.3 / AT a. For analogue instruments like measuring cylinders or rulers, the absolute uncertainty of a single reading is generally assumed to be half of the smallest division. Since the smallest division is $1\ cm^3$, the uncertainty is $\pm 0.5\ cm^3$.
A student is creating a dilution series. They take $1\ cm^3$ of a $100\%$ stock solution and add it to $9\ cm^3$ of water in Tube 1. They then take $1\ cm^3$ from Tube 1 and add it to $9\ cm^3$ of water in Tube 2. What is the concentration in Tube 2?
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This is a serial dilution. Each step dilutes the previous tube by a factor of 10.
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Answer: $1\%$
AT c. Tube 1 is a 1-in-10 dilution, so its concentration is $100 / 10 = 10\%$. Tube 2 is a 1-in-10 dilution of Tube 1, so its concentration is $10 / 10 = 1\%$.
Which of the following is a strict convention when producing a scientific biological drawing from a microscope observation?
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Biological drawings are meant to clearly record anatomical structures, not to be artistic sketches.
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Answer: Lines must be clear, continuous, and unshaded.
AT e. Scientific drawings must use sharp, continuous lines (no sketching). There must be no shading or stippling. Label lines should be drawn with a ruler and must never cross.
When using living organisms (like woodlice or maggots) in experimental procedures, what ethical consideration must be strictly adhered to?
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Biological ethics applies to the treatment of all living subjects.
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Answer: The organisms must be handled carefully to avoid stress or harm, and must be returned safely to their natural habitat immediately after the experiment.
AT h: safely and ethically use organisms. Ethical practice dictates minimizing distress to live subjects and returning them unharmed to their natural environment once data collection is complete.
A student calibrates their eyepiece graticule at $x400$ magnification. They find that $40$ eyepiece divisions equal $10$ divisions on the stage micrometer. If one stage division is $0.1\ mm$ ($100\ \mu m$), what is the length of one eyepiece division?
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$10$ stage divisions = $10 \times 100\ \mu m = 1000\ \mu m$. Divide this total length by the $40$ eyepiece divisions.
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Answer: $25\ \mu m$
AT d: Use of a light microscope and a stage micrometer. $10$ stage divisions = $1000\ \mu m$. If $40$ eyepiece divisions (epu) cover this distance, then $1$ epu = $1000 / 40 = 25\ \mu m$.
To create a serial dilution decreasing by a factor of 10 each time, a student starts with $10\ cm^3$ of a $1.0\ mol\ dm^{-3}$ solution. To make the next concentration ($0.1\ mol\ dm^{-3}$) with a total volume of $10\ cm^3$, what must they do?
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You want a 1-in-10 dilution. This means 1 part original solution to 9 parts water.
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Answer: Transfer $1\ cm^3$ of the $1.0\ mol\ dm^{-3}$ solution into a new tube and add $9\ cm^3$ of distilled water.
AT c: Use of serial dilutions. To dilute by a factor of $10$ and end up with $10\ cm^3$, take $1$ part stock ($1\ cm^3$) and add $9$ parts diluent ($9\ cm^3$).
A student uses an eyepiece graticule to measure the diameter of a cell. The cell spans $15$ eyepiece units. If the calibration shows that $1$ eyepiece unit equals $4\ \mu m$, what is the real diameter of the cell?
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Simply multiply the number of units by the value of one unit.
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Answer: $60\ \mu m$
AT g. Number of eyepiece units $\times$ length of one unit = real size. $15 \times 4\ \mu m = 60\ \mu m$.
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